\(\text{Áp dụng tính chất day tỉ số bằng nhau.Ta có:}\\\dfrac{x+5}{2}=\dfrac{y-2}{3}=\dfrac{(x+5)-(y-2)}{2-3}=\dfrac{x+5-y+2}{-1}=\dfrac{(x-y)+(5+2)}{-1}\\=\dfrac{-10+7}{-1}=3.\\\Rightarrow \dfrac{x+5}{2}=3\Rightarrow x+5=6\Rightarrow x=1.\\\Rightarrow \dfrac{y-2}{3}=3\Rightarrow y-2=9\Rightarrow y=11.\\\text{Vậy }x=1;y=11.\)
