\(\dfrac{x-2}{5}=\dfrac{x}{3}\)

\(\dfrac{x+23}{x+40}=\dfrac{3}{4}\)

A=\(\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+--.+\dfrac{1}{2^{2017}}\)

B=1+2+22+23+=.+22017

Các câu hỏi liên quan