Đáp án:
$\left \{ {{16u+16v=1} \atop {3u+6v=\dfrac{1}{4}}} \right.$
$⇔$$\left \{ {{48u+48v=3} \atop {48u+96v=4}} \right.$
$⇔$$\left \{ {{-48v=-1} \atop {3u+6v=\dfrac{1}{4}}} \right.$
$⇔$$\left \{ {{v=\dfrac{1}{48}} \atop {3u+6.\dfrac{1}{48}=\dfrac{1}{4}}} \right.$
$⇔$$\left \{ {{v=\dfrac{1}{48}} \atop {u=\dfrac{1}{24}}} \right.$
$\text{Vậy hệ phương trình có nghiệm (u; v) =($\dfrac{1}{24} ; \dfrac{1}{48}$)}$
