Nguyên hàm $\int{{\frac{{{{{(x-1)}}^{2}}}}{{{{{(2x+1)}}^{4}}}}dx}}$ bằng? 
A. ${{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$ 
B. $\frac{1}{6}{{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$ 
C. $\frac{1}{9}{{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$ 
D. $\frac{1}{3}{{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$

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