Tìm m để hàm số liên tục của hàm số tại \(x = 1\)
\(f\left( x \right) = \left\{ \begin{array}{l}\dfrac{{\sqrt {x + 3} + {x^2} + x - 4}}{{x - 1}}\,\,khi\,\,x \ge - 3,\,\,x \ne 1\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,m\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,x = 1\end{array} \right.\)
A.\(m = \dfrac{{11}}{4}\).
B.\(m = \dfrac{{13}}{4}\).
C.\(m = \dfrac{{9}}{4}\).
D.\(m = \dfrac{{15}}{4}\).
\(f\left( x \right) = \left\{ \begin{array}{l}\dfrac{{\sqrt {x + 3} + {x^2} + x - 4}}{{x - 1}}\,\,khi\,\,x \ge - 3,\,\,x \ne 1\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,m\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,x = 1\end{array} \right.\)
A.\(m = \dfrac{{11}}{4}\).
B.\(m = \dfrac{{13}}{4}\).
C.\(m = \dfrac{{9}}{4}\).
D.\(m = \dfrac{{15}}{4}\).
Loga
Hóa Học lớp 12
