Em tham khảo nha:
\(\begin{array}{l}
a)\\
2Na + 2{H_2}O \to 2NaOH + {H_2}\\
2K + 2{H_2}O \to 2KOH + {H_2}\\
NaOH + HCl \to NaCl + {H_2}O\\
KOH + HCl \to KCl + {H_2}O\\
hh:Na(a\,mol),K(b\,mol)\\
n{H_2} = \dfrac{{4,48}}{{22,4}} = 0,2\,mol\\
0,5a + 0,5b = 0,2\\
58,5a + 74,5b = 26,6\\
\Rightarrow a = b = 0,2\\
m = mNa + mK = 0,2 \times (23 + 39) = 12,4g\\
b)\\
FeO + {H_2} \to Fe + {H_2}O\\
nFeO = n{H_2} = 0,2\,mol\\
mFeO = 0,2 \times 72 = 14,4g\\
c)\\
nHCl = 0,2 + 0,2 = 0,4\,mol\\
{C_M}HCl = \dfrac{{0,4}}{{0,4}} = 1M
\end{array}\)
