a/ (\(\dfrac{1}{5}\)x-2)(3x-2) ( Câu này mình không chắc đúng không :v )
= \(\dfrac{3}{5}\)x2-6x-\(\dfrac{2}{5}\) x+4
= \(\dfrac{3}{5}\) x2 - \(\dfrac{32}{5}\)x + 4
b/ 3x3yz : 2x2y
= \(\dfrac{3}{2}\)xz
c/
x - 2 x 2 x 3 - 8 - x 3 + 2x 2 + 2x 2 - 8 + 2x - 2x 2 + 4x + 4x - 8 + 4 - 4x + 8 0