Đáp án: \(\left[ \begin{array}{l}x=-π+kπ\\x=\dfrac{π}{2}+kπ\end{array} \right.\)
Giải thích các bước giải:
`sin (2x+ π/6) = -1/2`
`<=> sin (2x+ π/6) = sin (-π/6)`
`<=>` \(\left[ \begin{array}{l}2x+\dfrac{π}{6}=\dfrac{-π}{6}+k2π\\2x+\dfrac{π}{6}=π-\dfrac{-π}{6} +k2π\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=-π+kπ\\x=\dfrac{π}{2}+kπ\end{array} \right.\)
