\(x+\dfrac{1}{x}=x^2+\dfrac{1}{x^2}\)
\(x+\dfrac{1}{x}=x^2+\dfrac{1}{x^2}\left(ĐKXĐ:xe0\right)\)
\(\Leftrightarrow\dfrac{x^3+x}{x^2}=\dfrac{x^4+1}{x^2}\)
\(\Rightarrow x^3+x=x^4+1\)
\(\Leftrightarrow x^3-x^4-1+x=0\)
\(\Leftrightarrow x^3\left(1-x\right)-\left(1-x\right)=0\)
\(\Leftrightarrow\left(1-x\right)\left(x^3-1\right)=0\)
\(\Leftrightarrow\left(1-x\right)\left(x-1\right)\left(x^2+x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}1-x=0\\x-1=0\\x^2+x+1=0\left(VN\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=1\end{matrix}\right.\)
Vậy =-...
\(\dfrac{x-2}{x+2}\)-\(\dfrac{3}{x-2}\)=\(\dfrac{2\times\left(x-11\right)}{x^2-4}\)
Giải phương trình:
a,\(\dfrac{x+1}{x^2+x+1}\)-\(\dfrac{x-1}{x^2-x+1}\)=\(\dfrac{3}{x.\left(x^4+x^2+1\right)}\)
b,\(\dfrac{1}{4x^2-12x+9}\)-\(\dfrac{3}{9-4x^2}=\dfrac{4}{4x^2+12x+9}\)
c,\(\dfrac{2}{\left(1-3y\right).\left(3y+11\right)}=\dfrac{1}{9y^2-y+1}-\dfrac{3}{\left(3y+11\right)^2}\)
d,\(\dfrac{x+5}{x-1}=\dfrac{x+1}{x-3}-\dfrac{8}{x^2-4x+3}\)
Giúp mk nha mn
|4-5x|+6x=7
Giải phương trình x+3/x+1+x-2/x=2
bằng cách phân tích vế trái thành nhân tử giải cadc pt sau:
a) x^3-3x^2+3x-1=0
b) (2x-5)²-(x+2)²=0
\(\dfrac{2}{x-2}+\dfrac{3}{x-3}=\dfrac{3}{x-4}\)
giúp mình với. Mình sẽ hậu tạ
giải các bất pt sau:
a, 4x-10<0
b, 2x+x+12\(\ge0\)
c, x-5\(\ge3-x\)
d, 7-3x>9-x
đ, 2x-(3-5x)\(\le4\left(x+3\right)\)
e, 3x-6+x<9-x
f, 2t-3+5t\(\ge\)4t+12
g, 3y-2\(\le2y-3\)
h,3-4x+24+6x\(\ge x+27+3x\)
i, 5-(6-x)\(\le4\left(3-2x\right)\)
k, 5(2x-3)- 4(5x-7)\(\ge19-2\left(x+11\right)\)
l, \(\dfrac{2x-5}{3}-\dfrac{3x-1}{2}< \dfrac{3-x}{5}-\dfrac{2x-1}{4}\)
m, \(5x-\dfrac{3-2x}{2}>\dfrac{7x-5}{2}+x\)
n, \(\dfrac{7x-2}{3}-2x< 5-\dfrac{x-2}{4}\)
Các bn giải giúp mk bài này nha!!!
\(\dfrac{x+3}{x+1}\)+\(\dfrac{x-2}{x}\)=2
(X+1/x-2)-(5/x+2)=(12/x^2-4)+1
Tìm x để -4x2/3-x>0
Loga.vn - Cộng Đồng Luyện Thi Trực Tuyến