Giải phương trình:
a,x+1x2+x+1\dfrac{x+1}{x^2+x+1}x2+x+1x+1-x−1x2−x+1\dfrac{x-1}{x^2-x+1}x2−x+1x−1=3x.(x4+x2+1)\dfrac{3}{x.\left(x^4+x^2+1\right)}x.(x4+x2+1)3
b,14x2−12x+9\dfrac{1}{4x^2-12x+9}4x2−12x+91-39−4x2=44x2+12x+9\dfrac{3}{9-4x^2}=\dfrac{4}{4x^2+12x+9}9−4x23=4x2+12x+94
c,2(1−3y).(3y+11)=19y2−y+1−3(3y+11)2\dfrac{2}{\left(1-3y\right).\left(3y+11\right)}=\dfrac{1}{9y^2-y+1}-\dfrac{3}{\left(3y+11\right)^2}(1−3y).(3y+11)2=9y2−y+11−(3y+11)23
d,x+5x−1=x+1x−3−8x2−4x+3\dfrac{x+5}{x-1}=\dfrac{x+1}{x-3}-\dfrac{8}{x^2-4x+3}x−1x+5=x−3x+1−x2−4x+38
Giúp mk nha mn
d. ĐKXĐ: x khác 1, x khác 3
x+5x−1=x+1(x−3)−8x2−4x+3\dfrac{x+5}{x-1}=\dfrac{x+1}{\left(x-3\right)}-\dfrac{8}{x^2-4x+3}x−1x+5=(x−3)x+1−x2−4x+38
⇔(x−3)(x+5)(x−1)(x−3)=(x+1)(x−1)(x−1)(x−3)−8(x−1)(x−3)\Leftrightarrow\dfrac{\left(x-3\right)\left(x+5\right)}{\left(x-1\right)\left(x-3\right)}=\dfrac{\left(x+1\right)\left(x-1\right)}{\left(x-1\right)\left(x-3\right)}-\dfrac{8}{\left(x-1\right)\left(x-3\right)}⇔(x−1)(x−3)(x−3)(x+5)=(x−1)(x−3)(x+1)(x−1)−(x−1)(x−3)8 ⇔x2+2x−15=x2−1−8\Leftrightarrow x^2+2x-15=x^2-1-8⇔x2+2x−15=x2−1−8
⇔2x−15+1+8=0\Leftrightarrow2x-15+1+8=0⇔2x−15+1+8=0
⇔2x−6=0\Leftrightarrow2x-6=0⇔2x−6=0
⇔x=3\Leftrightarrow x=3⇔x=3 (loại)
Vậy pt vô nghiệm
|4-5x|+6x=7
Giải phương trình x+3/x+1+x-2/x=2
bằng cách phân tích vế trái thành nhân tử giải cadc pt sau:
a) x^3-3x^2+3x-1=0
b) (2x-5)²-(x+2)²=0
2x−2+3x−3=3x−4\dfrac{2}{x-2}+\dfrac{3}{x-3}=\dfrac{3}{x-4}x−22+x−33=x−43
giúp mình với. Mình sẽ hậu tạ
giải các bất pt sau:
a, 4x-10<0
b, 2x+x+12≥0\ge0≥0
c, x-5≥3−x\ge3-x≥3−x
d, 7-3x>9-x
đ, 2x-(3-5x)≤4(x+3)\le4\left(x+3\right)≤4(x+3)
e, 3x-6+x<9-x
f, 2t-3+5t≥\ge≥4t+12
g, 3y-2≤2y−3\le2y-3≤2y−3
h,3-4x+24+6x≥x+27+3x\ge x+27+3x≥x+27+3x
i, 5-(6-x)≤4(3−2x)\le4\left(3-2x\right)≤4(3−2x)
k, 5(2x-3)- 4(5x-7)≥19−2(x+11)\ge19-2\left(x+11\right)≥19−2(x+11)
l, 2x−53−3x−12<3−x5−2x−14\dfrac{2x-5}{3}-\dfrac{3x-1}{2}< \dfrac{3-x}{5}-\dfrac{2x-1}{4}32x−5−23x−1<53−x−42x−1
m, 5x−3−2x2>7x−52+x5x-\dfrac{3-2x}{2}>\dfrac{7x-5}{2}+x5x−23−2x>27x−5+x
n, 7x−23−2x<5−x−24\dfrac{7x-2}{3}-2x< 5-\dfrac{x-2}{4}37x−2−2x<5−4x−2
Các bn giải giúp mk bài này nha!!!
x+3x+1\dfrac{x+3}{x+1}x+1x+3+x−2x\dfrac{x-2}{x}xx−2=2
(X+1/x-2)-(5/x+2)=(12/x^2-4)+1
Tìm x để -4x2/3-x>0
x+2x−2+x−2x+2=2x−1x2−4\dfrac{x+2}{x-2}+\dfrac{x-2}{x+2}=\dfrac{2x-1}{x^2-4}x−2x+2+x+2x−2=x2−42x−1
giải pt:
1x−2−6x+3=56−x2−x\dfrac{1}{x-2}-\dfrac{6}{x+3}=\dfrac{5}{6-x^2-x}x−21−x+36=6−x2−x5
