Giải phương trình:
2x−2+3x−3=3x−4\dfrac{2}{x-2}+\dfrac{3}{x-3}=\dfrac{3}{x-4}x−22+x−33=x−43
giúp mình với. Mình sẽ hậu tạ
=> 2(x−3)(x−4)+3(x−2)(x−4)−3(x−2)(x−3)(x−2)(x−3)(x−4)=0\dfrac{2\left(x-3\right)\left(x-4\right)+3\left(x-2\right)\left(x-4\right)-3\left(x-2\right)\left(x-3\right)}{\left(x-2\right)\left(x-3\right)\left(x-4\right)}=0(x−2)(x−3)(x−4)2(x−3)(x−4)+3(x−2)(x−4)−3(x−2)(x−3)=0
Rồi tự nhân ra thôi nhé ( dài quá tớ lười mà )
giải các bất pt sau:
a, 4x-10<0
b, 2x+x+12≥0\ge0≥0
c, x-5≥3−x\ge3-x≥3−x
d, 7-3x>9-x
đ, 2x-(3-5x)≤4(x+3)\le4\left(x+3\right)≤4(x+3)
e, 3x-6+x<9-x
f, 2t-3+5t≥\ge≥4t+12
g, 3y-2≤2y−3\le2y-3≤2y−3
h,3-4x+24+6x≥x+27+3x\ge x+27+3x≥x+27+3x
i, 5-(6-x)≤4(3−2x)\le4\left(3-2x\right)≤4(3−2x)
k, 5(2x-3)- 4(5x-7)≥19−2(x+11)\ge19-2\left(x+11\right)≥19−2(x+11)
l, 2x−53−3x−12<3−x5−2x−14\dfrac{2x-5}{3}-\dfrac{3x-1}{2}< \dfrac{3-x}{5}-\dfrac{2x-1}{4}32x−5−23x−1<53−x−42x−1
m, 5x−3−2x2>7x−52+x5x-\dfrac{3-2x}{2}>\dfrac{7x-5}{2}+x5x−23−2x>27x−5+x
n, 7x−23−2x<5−x−24\dfrac{7x-2}{3}-2x< 5-\dfrac{x-2}{4}37x−2−2x<5−4x−2
Các bn giải giúp mk bài này nha!!!
x+3x+1\dfrac{x+3}{x+1}x+1x+3+x−2x\dfrac{x-2}{x}xx−2=2
(X+1/x-2)-(5/x+2)=(12/x^2-4)+1
Tìm x để -4x2/3-x>0
x+2x−2+x−2x+2=2x−1x2−4\dfrac{x+2}{x-2}+\dfrac{x-2}{x+2}=\dfrac{2x-1}{x^2-4}x−2x+2+x+2x−2=x2−42x−1
giải pt:
1x−2−6x+3=56−x2−x\dfrac{1}{x-2}-\dfrac{6}{x+3}=\dfrac{5}{6-x^2-x}x−21−x+36=6−x2−x5
giải phương trình:
1x2+5x+4+1x2+11x+28+1x2+17x+70+1x2+23x+130=413\dfrac{1}{x^2+5x+4}+\dfrac{1}{x^2+11x+28}+\dfrac{1}{x^2+17x+70}+\dfrac{1}{x^2+23x+130}=\dfrac{4}{13}x2+5x+41+x2+11x+281+x2+17x+701+x2+23x+1301=134
Giải bất phương trình
−x2+4x−10x2+1<0\dfrac{-x^2+4x-10}{x^2+1}< 0x2+1−x2+4x−10<0
Cho a,b ≥\ge≥1. Chứng minh : a2 + b2 ≥\ge≥ a + b
1x2+y2+1xy≥6\dfrac{1}{x^2+y^2}+\dfrac{1}{xy}\ge6x2+y21+xy1≥6