\(\dfrac{29}{3}\cdot\dfrac{7}{5}-\dfrac{11}{3}:\dfrac{5}{7}=\dfrac{29}{3}\cdot\dfrac{7}{5}-\dfrac{11}{3}\cdot\dfrac{7}{5}\)
\(=\dfrac{7}{5}\cdot\left(\dfrac{29}{3}-\dfrac{11}{3}\right)=\dfrac{7}{5}\cdot\dfrac{18}{3}=\dfrac{7}{5}\cdot6=\dfrac{42}{5}\)